Demostrar que el triangulo abc con vertice

A=(3,3)

B=(-3,-3)

C=(-33, 33 )

es equilatero.

AB= (-3,-3)(-3,-3)+(-3,-3)(-3,-3)

AB = 8.48

BC= (-33+3)(-33+3)+(33+3)(33+3)



BC= 8.48

CA= (3+33)(3+33)+(3-33)(3-33)

CA=8.48